Counter On News
import re
from collections import Counter
words = re.findall(r'\w+', open('../../../assets/news.txt').read().lower())
Counter(words).most_common(10)
[('a', 37),
('and', 36),
('to', 30),
('the', 27),
('that', 24),
('of', 18),
('employees', 17),
('is', 14),
('in', 14),
('as', 13)]