Counter On News

import re
from collections import Counter
words = re.findall(r'\w+', open('../../../assets/news.txt').read().lower())
Counter(words).most_common(10)
[('a', 37),
 ('and', 36),
 ('to', 30),
 ('the', 27),
 ('that', 24),
 ('of', 18),
 ('employees', 17),
 ('is', 14),
 ('in', 14),
 ('as', 13)]