Counter Simple

from collections import Counter

a = Counter("Hello there, How are you")

a

Counter({' ': 4,
         ',': 1,
         'H': 2,
         'a': 1,
         'e': 4,
         'h': 1,
         'l': 2,
         'o': 3,
         'r': 2,
         't': 1,
         'u': 1,
         'w': 1,
         'y': 1})

def isin(a, b):
    return not Counter(a) - Counter(b)

isin("hel my frend", "hello my friend")

True

More:

https://stackoverflow.com/questions/56189821/how-to-check-if-a-string-is-a-substring-of-another-even-if-not-in-order