Sort Dictionary By Value

20 Apr 2019

dict = {
    'one' : 8,
    'two' : 1,
    'three' : 12
}

dict

{'one': 8, 'three': 12, 'two': 1}

import operator


sorted_x = sorted(dict.items(), key=operator.itemgetter(1))

sorted_x

[('two', 1), ('one', 8), ('three', 12)]

type(sorted_x)

list

import collections

sorted_dict = collections.OrderedDict(dict)

sorted_dict

OrderedDict([('one', 8), ('two', 1), ('three', 12)])

# Reverse sort

reverse_dict= sorted(dict.items(), key=lambda x: x[1], reverse=True)

reverse_dict

[('three', 12), ('one', 8), ('two', 1)]

for x in reverse_dict:
    print(x[0], "==>", x[1])

three ==> 12
one ==> 8
two ==> 1