30-Substring-With-Concatenation-Of-All-Words
Sat 17 May 2025
https://leetcode.com/problems/substring-with-concatenation-of-all-words
import pyutil as pyu
pyu.get_local_pyinfo()
print(pyu.ps2("python-dotenv"))
from typing import List
class Solution:
def findSubstring(self, s: str, words: List[str]) -> List[int]:
if len(s) == 0 or words == []:
return []
k = len(words)
n = len(words[0])
ans = []
count = Counter(words)
for i in range(len(s) - k * n + 1):
seen = defaultdict(int)
j = 0
while j < k:
word = s[i + j * n: i + j * n + n]
seen[word] += 1
if seen[word] > count[word]:
break
j += 1
if j == k:
ans.append(i)
return ans
new Solution().findSubstring()
Score: 5
Category: leetcode