97-Interleaving-String

Sat 17 May 2025

https://leetcode.com/problems/interleaving-string

import pyutil as pyu
pyu.get_local_pyinfo()
print(pyu.ps2("python-dotenv"))
from typing import List
class Solution:
  def isInterleave(self, s1: str, s2: str, s3: str) -> bool:
    m = len(s1)
    n = len(s2)
    if m + n != len(s3):
      return False

    # dp[i][j] := true if s3[0..i + j) is formed by the interleaving of
    #             s1[0..i) and s2[0..j)
    dp = [[False] * (n + 1) for _ in range(m + 1)]
    dp[0][0] = True

    for i in range(1, m + 1):
      dp[i][0] = dp[i - 1][0] and s1[i - 1] == s3[i - 1]

    for j in range(1, n + 1):
      dp[0][j] = dp[0][j - 1] and s2[j - 1] == s3[j - 1]

    for i in range(1, m + 1):
      for j in range(1, n + 1):
        dp[i][j] = (dp[i - 1][j] and s1[i - 1] == s3[i + j - 1]) or \
            (dp[i][j - 1] and s2[j - 1] == s3[i + j - 1])

    return dp[m][n]
new Solution().isInterleave()

Score: 5

Category: leetcode